6x^2-23x=20

Solution for 6x^2-23x=20 equation:

6x^2-23x=20

We move all terms to the left:

6x^2-23x-(20)=0

a = 6; b = -23; c = -20;
Δ = b2-4ac
Δ = -232-4·6·(-20)
Δ = 1009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{1009}}{2*6}=\frac{23-\sqrt{1009}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{1009}}{2*6}=\frac{23+\sqrt{1009}}{12}
$